Unsigned char numberChar = testValue // 255 So the second is 1, the third is 2, and so on. OK, but why the maximum value of a byte is 255 and not 256?
So every type is set at the maximum value because they are a multiple of each maximum. Indeed, with an unsigned short, we will be able to use this type up a value of 65535 in decimalīut in our example, we're going to use a huge value: 18,446,744,073,709,551,615.Īnd what we'll have will be the max value of each type!īecause this huge value is the maximum value of an unsigned long long. Wow, this is still confuse? Let's continue! If we wanted to have a such value, we would have to use another type, for example an unsigned short or an uint16_t equal to 2 bytes or 16 bits. So we won't be able to have a value of 256 in a char (or a byte). until 255 (Max value of a char or 1 byte) So if we put a value of 256, our result would be 0.įor example if we added +1 for each number below, we'd have: Why? Because 255 is the maximum value of an unsigned char or an uint8_t.
#ATMEL STUDIO EQUIVALENT FOR MAC CODE#
In the code part we will see that the number8 variable has a result of 255. It's not so easy to understand all these things, but keep trying, it will be clearer after the end of this tutorial. Notice that 0xFFFFFFFFFFFFFFFF is the same as 18, 446, 744, 073, 709, 551,615 and this is the maximum value possible for an unsigned long long, depending on your processor architecture (as gineera said in its comment). We're going to use a variable called testValue equal to 0xFFFFFFFFFFFFFFFF. It turns out that they are equal respectively to: unsigned char, unsigned short, unsigned int and unsigned long long. You are likely wondering what are uint8_t, uint16_t, uint32_t and uint64_t.
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